(PLEASE HELP) A red die is tossed and then a green die is tossed. What is the probability that the red die shows a number larger than three or the green die shows a number less than three? Make sure your answer is reduced.

2/3

Step-by-step explanation:

Well, it supplied the formula, so let's start from there.

    P(A or B) = P(A) + P(B) - P(A and B)

Let A = the probability that the red die shows a number larger than three

Let B = the probability that the green die shows a number less than three

I'm assuming they both have 6 numbers on them, like a regular die.

    So there are 3 possibilities that are larger than 3 (4, 5, and 6) and 6 total possibilities, so A = 3/6.

    There are 2 possibilities that are less than 3 (1 and 2) and 6 total possibilities, so B = 2/6.

Plug that into the formula.

    P(A or B) = 3/6 + 2/6 - P(A and B)

Now we have to subtract the probability that both A and B happen, which is 3/6 * 2/6 = 6/36 = 1/6.

    P(A or B) = 3/6 + 2/6 - 1/6

    P(A or B) = 4/6 = 2/3

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