What is the equation for the line with a slope of - 2/3 that passes through (0, -2)

y= -2/3x-2

Step-by-step explanation:

Since we have a point and a slope, we can use the point slope formula

m is the slope. In this case, m is -2/3

y1 is the y coordinate of the point. In this case, it is -2

x1 is the x coordinate. In this case it is 0.

We can substitute these values into the formula

y- -2= -2/3(x-0)

Distribute -2/3

y+2 = -2/3*x + -2/3*0

y+2= -2/3x+0

Subtract 2 from both sides. We want to get y by itself. This is because we want our line to be in y=mx+b form.

y+2-2= -2/3x+0-2

y= -2/3x -2

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: