On a coordinate plane, a line goes through (negative 2, negative 4) and (2, 2). A point is at (negative 3, 1).
What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

y – 1=Negative three-halves(x + 3)
y – 1=Negative two-thirds(x + 3)
y – 1= Two-thirds(x + 3)
y – 1= Three-halves(x + 3)

y – 1= Three-halves(x + 3)

Step-by-step explanation:

line goes through  (-2, -4) and (2, 2)

goes through (-3, 1)

slope =  (-4 - 2) / (-2 -2)  = -6/-4 = 3/2

1 =  (3/2)*-3 + b

1 = -9/2 + b

b = 1 + 9/2 = 11/2 = 5.5

y = (3/2)*x + 11/2

(y - 1) = (3/2)(x + 3)

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

answer: can you give the

step-by-step explanation: