What is the alternator-to-engine drive ratio if the
alternator turns at 1125 rpm when the engine is idling
at 500 rpm?

2.25 : 1

Step-by-step explanation:

Since the ratio is 1125 rpm for the alternator: 500 rpm for the engine, find the unit rate.

1125 : 500     Divide both sides by 500

2.25 : 1         For every turn of the engine, there are 2.25 turns of the alternator.

If this answer is correct, please make me Brainliest!

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take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: