In ΔFGH, the measure of ∠H=90°, HG = 48, FH = 55, and GF = 73. What ratio represents the tangent of ∠G?

55:48

Step-by-step explanation:

Given a right angles triangle ∆FGH

where  ∠H=90°, HG = 48, FH = 55, and GF = 73,

Based on the diagram attached

To find the tangent of angle G, we will use the concept of SOH CAH TOA in trigonometry identity.

According to TOA:

Tan ∠G = Opposite/Adjacent

Note that the opposite side will be the side facing the angle we are considering i.e ∠G

Opposite = 55

Adjacent will be the base of the triangle = 48

Tan∠G = 55/48

The ratio that represents the tangent of ∠G is 55:48

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

idk

step-by-step explanation: