What is the value of pq – 2q^2p, if p=2 and q=1?

A. -2 B. -1 C. 2 D. 4

The answer is A.

Step-by-step explanation:

You can do it by substituing the p value and q value into the expression :

Let p = 2,

Let q = 1,

pq - 2q²p

= (2)(1) - 2(1)²(2)

= 2 - 2(2)

= 2 - 4

= -2

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb