It takes 41.7 BTUs to heat a 5 gallon jug of water. What is the density of a gallon of water. Round your answer to the nearest hundredth

The density is 0.002 lb/cm^3

Step-by-step explanation:

1 BTU is neded to increment the temperature of 1 Lb of water by 1° F

Then if we need 41.7 BTU to increment 1°F of 5 gallons of water, this means that in the 5 gallons we have a mass of 41.7 lbs of water.

And as you know, density = mass/volume

now, 1 gallon = 3.78 liters = 3780 cm^3

then 5 gallons = 5*3780 cm^3  = 18900 cm^3

The density is D = 41.7Lb/18900 cm^3 = 0.002 lb/cm^3

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)