How many 3 number combinations are possible if you can't repeat the numbers? The numbers range from 0-39

49600

Step-by-step explanation: There are 40 ways to choose the first number

and there are 40 ways to choose the second number.

Now we take some examples to determine how many choices there are for

the third number

If the second number is 23, then the 3rd number cannot be any of these

9 numbers 19,20,21,22,23,24,25,26,or 27, since they are not at least 5

numbers away from 23.  Same for all other 40 second numbers.

Let's look at a second example which includes some on both sides of 0.

If second number is 2, we couldn't choose any of the 9 numbers 38,39,0,1,2,3,4,5,6.

So thats 40-9 or 31 choices for the 3rd number.

Answer 40*40*31 = 49600 ways.

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation: