Given the sequence 12, 6, 3, 3/2, identify the tenth term. show your work.

The common ratio can be found by dividing the second term by the first term.
6/12 = 1/2

an = a1 * r^(n-1)
n = term u want to find = 10
a1 = first term = 12
r = common ratio = 1/2

a10 = 12 * 1/2(10-1)
a10 = 12 * (1/2)^9
a10 = 12 * 1/512
a10 = 3/128 <

The third box is a function