What are the surface area and volume ratios of a cylinder change if the radius and height are multiplied by 5/4 ?

The ratio of the surface areas and volume is 8((5y+5x) /25xy)

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes.

Let us assume that the radius =x

Radius r=5x/4

And the height =y

Height h= 5y/4

We know that the total surface area of a cylinder is

A total = 2πrh+2πr²

We can factor out 2πr

A total = 2πr(h+r)

The volume of a cylinder is given as

v= πr²h

The surface area and volume ratios

Can be expressed as

2πr(h+r)/πr²h= 2(h+r)/rh

= (2h+2r)/rh= 2h/rh + 2r/rh

= 2/r + 2/h

= 2(1/r + 1/h)

Substituting our value of x and y

For radius and height we have

= 2(1/5x/4 + 1/5y/4)

=2(4/5x + 4/5y)

=2*4(1/5x + 1/5y)

= 8 (5y+5x/25xy)

Ratio of surface area = 25/16

Ratio of volume = 125/64

Step-by-step explanation:

The surface area and volume of a cylinder are given by the formulas:

Surface area = 2*(pi*r^2 + pi*r*h)

Volume = pi*r^2*h

If we increase the radius and height by 5/4, we have that:

New surface area = 2*(pi*(5/4*r)^2 + pi*(5/4)*r*(5/4)*h) = (5/4)^2 * 2*(pi*r^2 + pi*r*h) = (5/4)^2 * Surface area

New volume = pi*(5/4*r)^2*(5/4)*h = (5/4)^3 * pi*r^2*h = (5/4)^3 * Volume

So the ratios are:

ratio of surface area = New surface area / Surface area = (5/4)^2 = 25/16

ratio of volume = New volume / Volume = (5/4)^3 = 125/64

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3