Suppose that 40% of a population has brown hair. You want to estimate the probability that it will take at least a sample of four to find one person with brown hair. You set up a random digit simulation where 0, 1, 2, 3 represents a person with brown hair and 4, 5, 6, 7, 8, 9 represents a person that does not have brown hair. Which would constitute a trial for this simulation?

A

Step-by-step explanation:

A trail would consist of three random digits.

The problem asks for the probability that it will take at least a sample of four to find one person with brown hair. This implies that the first three people do not have brown hair. Therefore, a trial would consist of three random digits. A success is none of the three digits are 0, 1, 2, or 3. For example, 675 would be a success and a failure would be 792.

A

Step-by-step explanation:

USA testprep said...

A trail would consist of three random digits.

The problem asks for the probability that it will take at least a sample of four to find one person with brown hair. This implies that the first three people do not have brown hair. Therefore, a trial would consist of three random digits. A success is none of the three digits are 0, 1, 2, or 3. For example, 675 would be a success and a failure would be 792.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

bull

step-by-step explanation: