A plane is cruising at an altitude of 30,000 feet.
What is the distance, to the nearest mile, from
the plane to the horizon? *
(5 Points)
4000
c mi

Correct option: Third one: 213 mi

Step-by-step explanation:

The distance from the plane to the horizon is the segment EH in the figure.

The altitude of the plane is 30,000 feet, which is equal to 5.6818 miles, and that is the value of the segment ED.

The segment DC is equal segment CH, as they are the radius of the circle.

So know, to solve this problem, we can use Pythagoras' equation:

EC^2 = CH^2 + EH^2

(5.6818+4000)^2 = 4000^2 + EH^2

EH^2 = 4005.6818^2 - 4000^2

EH^2 = 45486.6828

EH = 213.2761 miles

Rounding to nearest mile, we have EH = 213 miles

Correct option: Third one.

could you reply to this with the question so i can ?

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation: