4 green marbles, 5 red marbles, and 2 yellow marbles are placed into a bag. One marble is chosen and replaced into the bag. A second marble is chosen. What is the probability a red marble and then a yellow marble are chosen? Write answer in simplest fraction form,

The probability is 10/121

Step-by-step explanation:

In this question, we are tasked with calculating probability.

The probability to be calculated is that we have an ordered selection of picking a red marble after which we pick a yellow marble.

Firstly let us know the total number of marbles we have. That will be 4 + 5 + 2 = 11 marbles

Probability of picking a red marble will be 5/11 while the probability of picking a yellow marble will be 2/11

Now, the probability of picking a red marble before a yellow marble will be mathematically equal to; P(r) * P(y) = 5/11 * 2/11 = 10/121

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

1,918

step-by-step explanation: