PLEASE HEL
Write an equation for the following situation. Solve, then check.
The calendar used by a society in the third century A. D. consisted of 365 days divided into 18 months. Every month contained the same number of days, with the five leftover days considered unlucky. How many days were in each of the months?

Let x represent the number of days in each of the months.

I think the answer is 20

Step-by-step explanation:

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

hope to and hope that my answer is brainliest.(follow me )

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x