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#5= 52^0 (52 degree)-- A

#6=107^0 --S

#7=100^0--H

#8=80^0--I

#9=100^0--H

#10=115^0--E

#11=65^0--U

#12=115^0--E

#13=36^0--T

#14=144^0--W

#15=36^0--T

#16=52^0--A

#17=23^0--D

#18=90^0--O

#19=36^0--T

#20=60^0--R

#21=30^0--Q

#22=60^0--R

Step-by-step explanation:

#5. A circle has 360 degree. half circle 180 degree; therefore 180^0-128^0= 52^0.

graph 3. #7,#8,#9, it has an angle 80 degree, so we can find #7=180^0-80^0=100^0, and #9=180^-80^0=100^0; therefore, #8=80^0, a  circle is always 360 degree.

other has the same logic

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v