Simplifying Complex fractions using any method

3ab

(b+a)

Step-by-step explanation:

3/a - 3/b

1/a^2 - 1/b^2

Multiply the top and bottom by a^2 b^2/ a^2/b^2 to clear the fractions

(3/a - 3/b) a^2 b^2

(1/a^2 - 1/b^2) a^2b^2

3ab^2 - 3 a^2 b

b^2 -  a^2

Factor out 3ab on the top

3ab( b-a)

b^2 -  a^2

The bottom is the difference of squares

3ab( b-a)

(b-a) (b+a)

Cancel like terms from the top and bottom

3ab

(b+a)

3ab/(b+a)

Step-by-step explanation:

Simplifying the numerator:

3/a - 3/b

3[1/a - 1/b]

Lcm is ab

3[(b - a)/ab]

Simplifying the denominator:

1/a² - 1/b²

Lcm: a²b²

(b² - a²)/(a²b²)

(b - a)(b + a)/(a²b²)

Numerator ÷ denominator

3[(b - a)/ab] ÷ (b - a)(b + a)/(a²b²)

3[(b - a)/ab] × a²b²/[(b - a)(b + a)]

3ab/(b + a)

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!