A triangle has vertices A(0,0),B(-3,6),and C(0,9). What are the coordinates of the triangle after a dilation with a scale factor of 3

the triangle after the dilation has the vertices A' = (0,0), B' = (-9, 18) and C' = (0, 27)

Step-by-step explanation:

If the dilation is from the origin, then we need to multiplicate each point by the scale factor, then each one of the vertices change as:

A' = 3*A = 3*(0,0) = (0, 0)

B' = 3*B = 3*(-3, 6) = (-3*3, 6*3) = (-9, 18)

C' = 3*C = 3*(0,9) = (0, 3*9) = (0, 27)

Then the triangle after the dilation has the vertices A' = (0,0), B' = (-9, 18) and C' = (0, 27)

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.