∆XYZ has vertices X(0, 3), Y(2, 0), and Z(4, 2). If you reflect ∆XYZ across the line x = 4, what will be the coordinates of the vertices of the image ∆X′Y′Z′?

A.) X′(4, 3), Y′(6, 0), and Z′(4, 2)

B.) X′(3, 0), Y′(0, 2), and Z′(2, 4)

C.) X′(4, 3), Y′(2, 0), and Z′(4, 2)

D.) X′(8, 3), Y′(6, 0), and Z′(4, 2)

D

Step-by-step explanation

Since we are reflecting across the x axis, all of the y coordinates will remain the same. You find the distance away from the x = 4, double it, and add that value to x. So,

X' is now (8,3)

Y' is now  (6,0)

Z' is now (4,2) because its x was 0, and anything * 0 = 0 so it does not move.

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.