In a bag of 60 candies, 36 are green and 45 have caramel in them. If the events of picking a green candy and picking a candy with caramel are independent, what is the probability of selecting two candies where the first is green and the second has caramel? Express your answer as a fraction in simplest form.

9/20

Step-by-step explanation:

Total number of candies =60

Number of Green candies, n(G)=36

Number of candies with caramel, n(C)=45

Since the events are independent, the probability of selecting two candies where the first is green and the second has caramel is given by:

P(GC)=P(G) X P(C)

The probability in its lowest form is 9/20.

abde or 1,2,4, 5 is the answer

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)