Find the value of tan (θ) for an angle θ in standard position with the term array that passes through the point (5, 9).

A

Step-by-step explanation:

Let's draw a picture (see attachment).

We know that this ray passes through (5, 9) in the first Quadrant and forms a right triangle if we drop a perpendicular line down from the point to the x-axis. We also know that opposite and adjacent sides of this triangle: opposite is 9 and adjacent is 5.

Tangent is opposite / adjacent, so we have:

tan(θ) = 9/5

The answer is A.

a.

Step-by-step explanation:

tan(theta) = opposite/adjacent

= 9/5

Since it's in the first quadrant, tan is positive