The store employees held a frog leaping contest. Frog #1 jumped a distance of 8 feet 3 inches. Frog #2 jumped 2 yards 36 inches. Which frog won the contest? By how much?

Frog 1 - 8 feet 3 inches =

8 feet x (1 yard/3 feet) = 2.667 Yards

3 inches x (1 foot /12 inches) x ( 1 yard / 3 feet) = 0.83 yards

So Frog 1 = 2.75 Yard

Frog 2 - 2 yards 36 inches

36 inches x (1 foot /12 inches) x (1 yard / 3 feet) = 1 Yard

So Frog 2 = 3 yards

Frog 2 won

It won by 3 - 2.75 = 0.25 Yards

0.25 yards x (3 feet / 1 yard) = 0.75 feet

0.75 feet x (12 inches /1 foot) = 9 inches

So Frog 2 won by 9 inches

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

answer: idk

step-by-step explanation: