What is the factorization of the polynomial below?
16x²-9
O A. (4x+3)(4x - 3)
O B. (4x - 3)(4x - 3)
O C. (8x - 3)(2x-3)
O D. (8x+3)(2x-3)

:)Brainliest pls??

(4x + 3)(4x - 3)

So, the answer is A.

Step-by-step explanation:

16x^2 - 9 is a difference of squares which can be factored using the formula:

x^2 - y^2 = (x + y) * (x - y)

16x^2 - 9

= (4x * 4x) - (3 * 3)

= (4x + 3)(4x - 3)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?