Mark rolls 2 fair dice and adds the results from each.
Work out the probability of getting a total that is a factor of 18.

1/3

Step-by-step explanation:

The sample space for two dice is given as:

The Sample space for the total of each pair is:

Total Sample Space, n(S)=36

Factors of 18 are 1,2,3,6,9 and 18

Let Event A be the event that the total of each pair is a factor of 18.

Sample Space of A is:

n(A)=12

Therefore, the probability of A

P(A)=n(A)/n(S)=12/36=1/3

The probability of getting a total that is a factor of 18 is One-Third.

is there a question here?

step-by-step explanation:

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )