Consider the complex numbers p=1 - 3i and q = x + (2x + 1)i,
Find the values of x that satisfy the equation p = q

Solve the inequality Re(pg) +8 < (Im(pq))?

x = 1 - i(3 - 2x - 1)

Step-by-step explanation:

One question per post, please.

We want to solve the equation p = q, where p = 1 - 3i and q = x + (2x + 1)i.

Expanding q, we get q = x + 2xI + i, so that p + q becomes

1 - 3i = x + 2xi + i

Solving for x by subtracing (2xi + 1) from both sides, we get:

1 - 3i - 2xi - i = x

This result could be left as is, or we could separate the real and imaginary parts:

x = 1 - i(3 - 2x - 1)

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.