The third term in a sequence is 11.
The term-to-term rule is "take away 4".
Write an expression, in terms of n, for the nth term of the sequence.
The third number is 12

Since the person hasn't specified I'll solve for both f(3) = 12 and f(3) = 11.

f(n) = 20 - 4(fn-1) is the formula for when third term is 12

f(n) = 21 -4(n-1) when f(3) = 11

Step-by-step explanation:

Okay since we know d = -4, we can start to make an explicit rule.

But first, we need the first term.

If f(3) = 12, we know f(1) = 20

So.

f(n) = 20 - 4(n-1) when f(3) = 12

___

For f(3) = 11, we know f(1) = 21

So.

f(n) = 21 -4(n-1) when f(3) = 11

u bout ugly as   a mf

step-by-step explanation: lol

$650 per month plus utilities

step-by-step explanation:

just based on the info you gave, it would seem more cost effective to rent at $650 per month plus utilities.   if utilities are, in fact, $150 per month, your monthly living costs would be $800 as opposed to the other option of $825.