Nine tokens are black on one side and white on the other. Initially, four tokens have the black side up. In each turn you have to flip three tokens. What is the least number of turns you need to have all tokens showing the same color?

2 movements

Step-by-step explanation:

In this case what we will do is name the white chips "W" and the black ones "B". If there are 9 tiles and 4 are in black then the rest, that is 5, in white, like this:

B-B-B-B-W-W-W-W-W

First movement, in turn we can flip 3 tiles, in this case we flip two blacks and one white, it would look like this:

W-W-B-B-B-W-W-W-W

The second movement is to turn the 3 black ones and thus they would all be blank

W-W-W-W-W-W-W-W-W

In other words, the smallest number of movements is 2.

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph