In engineering, the modulus of elasticity is a way to measure how much an object deforms along an axis when opposing forces are applied among that axis. The formula can be expressed as E= (F2-F1)L0/(S2-S1)A, where E is the modulus of elasticity, F is the axial force, S is a deformation measure, L0 is the original length of the object, and A is the cross-sectional area.

Part A: Rearrange the elasticity formula to find the cross-sectional area, A.

Part B: Rearrange the elasticity formula to find the original length, L0, of the object.

I need to show my work so have an explanation

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?