When a baseball is thrown upward, its height is a function of time. If this function is given by formula h(t)=−16t^2+24t+5, what is the maximal height it reaches?
Nevermind I got it

the maximal height is 14.75 units of distance.

Step-by-step explanation:

We want to find the maximum height of the function

h(t) = -16*t^2 + 24*t + 5

In order to find the maximum, we need to find the value of t where the derivate of h(t) is equal to zero, then we evaluate our original function in that time.

The derivate of h(t) (or the vertical velocity) is:

h'(t) = 2*(-16)*t + 24 = -32*t + 24

we want to find the value of such:

0 = -32*t +24

32*t = 24

t = 24/32 = 0.75

Now we evaluate our height function in that value.

h(0.75) = -16*0.75^2 + 25*0.75 + 5 = 14.75 units

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17