The difference of the square of a number and 5 is equal to 4 times that number. Find the negative solution

x = - 3

Step-by-step explanation:

x² - 5 = 4

x² = 4 + 5

x² = 9

x = ± 3

the negative solution

x = - 3

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.