A teacher is lining up her class for a class picture. Jackson, William, and Rowan are best friends in the class. If there are 18 children in her class, what is the probability that Jackson is first, William is second, and Rowan is last?

1/4896

Step-by-step explanation:

This is a permutation problem, where order matters.

There are 18! ways to line up the class, and (18−3)!=15! ways where three children line up first, second, and third.

Then the probability is

P=15!18!=14896≈0.0002

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

ok

step-by-step explanation: