Dan has 50 coins that total $7.30. All of his coins are dimes, D, and quarters, Q. Write a system of equations that models this situation.

d + q = 50

0.10d + 0.25q = 7.30

Step-by-step explanation:

Since all of the 50 coins are dimes and quarters, we can write the equation:

d + q = 50, where d is the number of dimes and q is the number of quarters

Now, we know that dimes are 10 cents, or $0.10 and quarters are 25 cents, or $0.25. So, if we multiply 0.10 by d, we get the total value of the dimes, and if we multiply 0.25 by q, we get the total value of the quarters. The total value of all dimes and quarters is 7.30, so we have the equation:

0.10d + 0.25q = 7.30

Thus, the system is:

d + q = 50

0.10d + 0.25q = 7.30

Step-by-step explanation:

Step 1:  Find the first equation

We need to make an equation to represent the amount of coins.  Let dimes be represented with D and quarters with Q.  

Q + D = 50

Step 2:  Make the second equation

We need to make an equation to represent the total money together.  So, let dimes be represented with 0.10D and quarters with 0.25Q.

0.10D + 0.25Q = 7.30

Step 3:  Make the system of equations

Q + D = 50

0.10D + 0.25Q = 7.30

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

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step-by-step explanation: