Suppose the mean of a normally distributed population is 300, and 200 simple random samples are drawn from the population. At
a 68% confidence level, (one standard deviation from the mean), about how many of the samples' confidence intervals would you
expect to contain the population mean?
O 64
O 96

the required number of samples to contain the population mean = 136

Step-by-step explanation:

From the Empirical rule, If a data is normally distributed, then about 68% of the population lies within one standard deviation from mean.

Now, if we suppose that the mean of a normally distributed population is 300, and 200 simple random samples are drawn from the population. i.e. μ = 300

And;

Number of simple random samples: n = 200

Thus, by implication, we would expect about 68% of 200 samples confidence intervals to contain the population mean .

Hence,

Required number of samples = 68% of 200

This gives ;

0.68 x 200 = 136

Thus , the required number of samples = 136

europa2433

europa2433

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497