Is there a difference in the amount of airborne bacteria between carpeted and uncarpeted rooms? In an experiment, seven rooms were carpeted and seven were left uncarpeted. The rooms are similar in size and function. After a suitable period, the concentration of bacteria in the air was measured (in units of bacteria per cubic foot) in all of these rooms. The P-value for this test is greater than 0.25. Which of the following is a reasonable conclusion?A. There are outliers in these data, so we can't rely on the two-sample t test. B. This test is unreliable because the populations we're sampling from are heavily skewed. C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air. D. There is fairly strong evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Step-by-step explanation:

A. There are outliers in these data, so we can't rely on the two-sample t test.

There are no outliers, as the seven rooms for both sample have similar size and function.

B. This test is unreliable because the populations we're sampling from are heavily skewed.

We don't know if the populations are heavily skewed, but this effect should be appeased by the sampling.

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Correct conclusion, as the P-value is surely greater than the significance level (usually 0.10 at most).

D. There is fairly strong evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

There is no evidence as the P-value is greater than the significance level.

can i see the following ?

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.