Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160° respectively. find the direction and magnitude of these forces. round to two decimal places in all intermediate steps and in your final answer.

Given:
100 lbs at 50°
  50 lbs at 160°

1st vector:
100 lbs cos(50°) = 64.3 lbs ⇒ positive x direction
100 lbs sin(50°) =  76.60 lbs ⇒ positive y direction

2nd vector:
50 lbs cos(160°) = - 46.98 lbs ⇒ negative x direction
50 lbs sin(160°) = 17.10 lbs ⇒ positive y direction

x values:
64.3 lbs + (-46.98 lbs) = 17.32 positive x direction

y values:
76.60 lbs + 17.10 lbs = 93.70 positive y direction

Use Pythagorean theorem to find the resultant. 

Positive y direction = long leg of the right triangle
Positive x direction = short leg of the right triangle
Resultant = hypotenuse of the right triangle

a² + b² = c² 
93.70² + 17.32² = c²

8779.69 + 299.98 = c²

9079.67 = c²
√9079.67 = √c²
95.29 lbs = c 

Resultant is 95.29 lbs.

Direction of the resultang.

Θ = tan^-1 (93.7/17.32) = 79.53° above positive x axis.

9/12 is the answer because 3/4 times 3 each is 9/12

X=3 and y=4 is the answer