The length of a rectangle is three times as long as its width. The width of this rectangle is 6 inches smaller than its length. Find the length and the width. (It would also be interesting to know its area and perimeter!)

The length is 9in and the width is 3in

The perimeter is 24in and the area is 27in²

Step-by-step explanation:

To start we have to make 2 equations with the information that gave us the problem

l = length

w = width

w = l - 6in

l = 3w

we replace l in the first equation with (3w)

w = (3w) - 6in

w - 3w = -6in

-2w = -6in

w = -6in / (-2)

w = 3in

now we replace the value of w in the second equation

l = 3w

l = 3 (3in)

l = 9in

Now that we have the length and width we can calculate the perimeter and the area with the following formulas

p = perimeter

a = area

p = 2w + 2h

p = 2(3in) + 2(9in)

p = 6in + 18in

p = 24in

a = w * l

a = 3in * 9in

a = 27in²

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

the answer is a

step-by-step explanation: