Two friends argue over who brushes their teeth more often. To settle the
argument, they keep track of the number of mornings and nights they brush
and calculate a probability. These are shown in the table.
Braxton
Arabella
0.72
0.82
Probability of brushing
in morning
0.85
0.79
Probability of brushing
in evening
Who is more likely to brush both morning and evening? Assume all events are
independent.
O
A. Braxton. He has a 0.85 probability of brushing both times.
O
B. Arabella. She has a 0.65 probability of brushing both times.
O
C. Braxton. He has a 0.61 probability of brushing both times.
O
D. Arabella. She has a 0.82 probability of brushing both times.

c

step-by-step explanation:

at least i think its

answer: what are the answer choices?

step-by-step explanation:

agree

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)