A hot air balloon holds 2,200 cubic meters of helium. The density of helium is 0.1785 kilograms per cubic meter. How many kilograms of helium does the balloon contain, rounded to the nearest tenth of a kilogram?

The 392.7 kilogram  of helium does the balloon contain.

Step-by-step explanation:

Formula

Density = \frac{Mass}{Volume}

As given

A hot air balloon holds 2,200 cubic meters of helium.

The density of helium is 0.1785 kilograms per cubic meter.

Density =   0.1785 kilograms per cubic meter

Volume = 2200 cubic meters

Put in the formula

0.1785 = \frac{Mass}{2200}

Mass = 2200\times 0.1785

Mass = 392.7 kilogram

Therefore the 392.7 kilogram  of helium does the balloon contain.

i dont know nkw

step-by-step explanation:

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b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)