You have a bag of 12 blue marbles and 12 red marbles. each are labeled 1-12. so you have 24 marbles in total (1-12 for each color).
you draw one at random, put it back in the bag, and draw the second one.

what is the probability that the first marble is blue and the second marble is a 12?

Probability that the first marble is blue: 1/2 or 50%

Probably that the second is a 12: 1/12 or 8.3%

Step-by-step explanation:

There's 24 marbles in total with 12 of those being blue. So if you pull out a marble, there's a 12/24 chance of it being blue, which is reduced down to 1/2

Both the red and blue marbles are labeled 1-12, meaning there are two marbles labeled 12. So if you pull out a marble, there's a 2/24 chance that it'll be a 12, which is reduced down to 1/12. Remember that the first marble drawn is put back into the bag, so the second marble's probabilty isn't going to be 2/23

Hope this helps!

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

2,160 π

step-by-step explanation: