An airplane travels 125 miles horizontally during a decrease of 9miles vertically. (a) What is the angle of descent? (b) What is the distance of the plane’s path?

A = 85.87°

B = 124.67 miles

Step-by-step explanation:

To find the angle of depression, we'll have to know the angle at which the plane makes with vertical height.

See attached document for better illustration.

The plane travels horizontally for 125 miles and it was at a height of 9 miles.

To find the angle of depression, we'll use SOH CAH TOA to know which one suite the question.

SineΘ = opposite / hypothenus

CosΘ = adjacent / hypothenus

tanΘ = opposite / adjacent

The hypothenus is 125 miles and the adjacent is 9 miles. So we can use

CosΘ = adjacent / hypothenus

Cos Θ = 9 / 125

Cos Θ = 0.072

Θ = cos⁻0.072

Θ = 85.87°

The angle of depression which the plane makes is 85.87°

B. The distance the plane travels.

Since we have two side and unknown side in a right angle triangle, we can use pythagorean theorem

X² = y² + z²

X = 125

Y = 9

Z = ?

125² = 9² + z²

Z² = 125² - 9²

Z² = 15544

Z = √(15544)....take the square root of both sides.

Z = 124.67 miles.

The distance of the plane path is 124.67 miles

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0