The problem of finding the work done in lifting a payload from the surface of the moon is another type of work problem. Suppose the moon has a radius of R miles and the payload weighs P pounds at the surface of the moon (at a distance of R miles from the center of the moon). When the payload is x miles from the center of the moon (x ≥ R), the force required to overcome the gravitational attraction between the moon and the payload is given by the following relation: required force = f(x) = R2P x2 pounds. How much work would be needed to raise the payload from the surface of the moon (i. e., x = R) to an altitude of 3R miles above the surface of the moon (i. e., x = 4R)?

in lifting a payload from the surface of the moon is another type of work problem. ... ... Suppose The Moon Has A Radius Of R Miles And The Payload Weighs P Pounds At The Surface Of The Moon (at A Distance Of R Miles From ... When The Payload Is X Miles From The Center Of The Moon (X> R), The Force Required .

Step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°