21) Diana's school is selling tickets to their fall musical.
They sold 3 adult tickets and 8 children's tickets and made $66.
The next day they sold 8 adult tickets and 15 children's tickets
and took in$147.50. What is the price each of one adult ticket
and one child ticket?

Adult price is $10 and child is $4.5

Step-by-step explanation:

In this case we can solve it using a 2x2 system of equations, like this:

let x: price of adult tickets

let y: price of children tickets

So:

3*x + 8*y = 66

8*x + 15*y = 147.5 => x = (147.5 - 15*y)/8

Replacing, we are left with that:

3*((147.5 - 15*y)/8) + 8*y = 66

55.3125 - 5.625* y + 8* y = 66

8* y - 5.625* y= 66 - 55.3125

2.375* y = 10.6875

y = 10.6875/2.375

y = 4.5

Now to calculate x:

x = (147.5 - 15*4.5)/8

x = 10

which means the adult price is $10 and the child is $4.5

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: