Which table represents a quadratic function? A 2-column table with 6 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries 6, 3, 2, 3, 6. A 2-column table with 6 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 5, negative 3, negative 1, 1, 3. A 2-column table with 6 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 9, negative 4.5, 0, 4.5, 9. A 2-column table with 6 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries 0.25, 0.5, 1, 2, 4.

9514 1404 393

  A

Step-by-step explanation:

The attachment shows the tables and their respective first- and second-differences. The quadratic function is the one with non-zero constant second differences. That is the first table, A.

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Tables B and C are linear functions. Table D is exponential.

Table A has the equation ...

  f(x) = x^2 +2

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

which statement is true about the local minimum of the graphed function?

over the interval [–4, –2], the local minimum is 0.

over the interval [–2, –1], the local minimum is 25.

over the interval [–1, 4], the local minimum is 0.

over the interval [4, 7], the local minimum is -7.