Mathematics, 05.05.2020 20:34 fredvales19

Determine the vertex of y = 3x^2- 6x – 5.

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Consider the vertex form of a parabola. Substitute the values of a a and b b into the formula d=b2a d = b 2 a . Simplify the right side. Cancel the common factor of 6 6 and 2 2 .

Step-by-step explanation:

the x value of the vertex in ax^2+bx+c is -b/2athe x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for xthe x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backthe x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5y=3-1the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5y=3-1y=2the x value of the vertex in ax^2+bx+c is -b/2ay value is just sub for x3x^2-6x+5x value of vertex is -(-6)/(2*3)=6/6=1sub backy=3(1)^2-6(1)+5y=3(1)-6+5y=3-1y=2vertex is (1,2)

Answer from: Quest

c. side angle side. u shares the same sides

By which rule are these triangles congruent? a) aas b) asa c) sas d) sss

Answer from: Quest

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

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Determine the vertex of y = 3x^2- 6x – 5....