A potential candidate for President has stated that she will run for office if at least 30% of Americans voice support for her candidacy. To make her decision she draws a random sample of 500 Americans. Suppose that in fact 35% of all Americans support her candidacy. What is the probability that the potential candidate will obtain a p^ ≥ 0.30 (and run for President)? Round your answer to four decimal places.

Probability that the potential candidate will run for President election is 0.0096.

Step-by-step explanation:

We are given that a potential candidate for President has stated that she will run for office if at least 30% of Americans voice support for her candidacy.

To make her decision she draws a random sample of 500 Americans. Suppose that in fact 35% of all Americans support her candidacy.

Let p = % of Americans voice support for her candidacy

The z score probability distribution for sample proportion is given by;

                               Z  =    ~ N(0,1)

where, = sample proportion of Americans support her candidacy = 35%

            n = sample of Americans = 500

Now, probability that the potential candidate will obtain a p^ ≥ 0.30 and run for President is given by = P( ≥ 0.30)

      P( ≥ 0.30) = P( ≥ ) = P(Z ≥ 2.34) = 1 - P(Z 2.34)

                                                                      = 1 - 0.9904 = 0.0096

The above probability is calculated by looking at the value of x = 2.34 in the z table which has an area of 0.9904.

Hence, the required probability is 0.0096.

30 people weigh 160 pounds or more

i think its a and d

step-by-step explanation: