The circle pictured below has center
and radius of 4 cm. Given that mZQPR = 170'ind the length of minor are QR to the nearest hundredth

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i think the answer is true

step-by-step explanation:

4+4+2x

or

2x+8

step-by-step explanation:

y=-2x+1500

step-by-step explanation:

+1500

2 over one