Upon hitting a bat, a baseball has a change in momentum of 16.5 kg-ms. What is the average
force applied to the baseball the time of impact is 0.00200 seconds?

The average force applied to the baseball is 8.25kN

Step-by-step explanation:

This problem bothers on the impulse of a force

We know that the change in momentum is expressed as

Ft= mv-mu

Given

Ft=16.5 kg-ms

Time t of impact =0.00200s

The force applied can be solved for

By making F subject of formula

F= (mv-mu)/t

F=16.5/0.002

F= 8250N

F= 8.25kN

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

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step-by-step explanation: