The exterior angles of a triangle are (2x+10), (3x+5), and (2x+40) 0.
i. Find the value of x.
ii. Find the smallest interior angle of the triangle.
iii. Find the largest interior angle of the triangle.

Step-by-step explanation:

i. (2x+10)+(3x+5)+(2x+40) = 360

2x+3x+2x+10+5+40= 360

7x+55 =360

7x=360-55

7x= 305

7. 7

x= 43.57=43.6

ii. 2x+10= 180

2x=180-10

2x= 170

2. 2

x=85

3x+5 =180

3x=180-5

3x=175

3. 3

x= 57.5

2x+40=180

2x=180-40

2x=140

2. 2

x= 70

From the above 3x+5 which is 57.5 is the smallest interior angle of the triangle

iii. The largest interior angle of the triangle is 2x+10 which is 85

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