I need help with this maths equation

The length of the side of a square is 20 cm.

Step-by-step explanation:

Part 1: Find the x

First, you know that all sides of a square are equal, therefore, these two equations should be equal.

6x - 1 = 4x+6

Now, you simplify.

You would move whichever like term you want (either 6x over to the side of 4x (or vice versa) or -1 to the side of the 6 (or vice versa)

In my case, I will move 4x over to the other side.

Now I have:

6x - 4x -1 = 6

You can subtract like terms, in this case 6x and 4x:

2x - 1 = 6

Now you do the same, just with the constant numbers.

You would move over the -1 to try isolate the variable. (Keep in mind that the sign (positive or negative) changes when you move it to the other side.

2x = 6 +1

2x = 7

Then, you want to leave x by itself, so you have to divided 2x by 2. What you do to that side, you have to do to the other side.

2x/2 = 7/2

x = 3.5

Part 2: Plugging x into the equation

Now, since you have to x, you have to put it in any of the equations. Keep on mind it doesn’t matter, since both sides are the same anyway.

I‘m going to use the side 6x -1.

You now have to subsitute 3.5 for the x.

You now have:

= 6 (3.5) -1

= 21 -1

= 20

Therefore, your side is equal to 20 cm.

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2