Suzanne owns a small business that employs 555 other people. Suzanne makes \$100{,}000$100,000dollar sign, 100, comma, 000 per year, and the other 555 employees make between \$40{,}000$40,000dollar sign, 40, comma, 000 and \$50{,}000$50,000dollar sign, 50, comma, 000 per year.
Suzanne decides to increase her salary by \$30{,}000$30,000dollar sign, 30, comma, 000 per year and leave the rest of the salaries the same.
How will increasing her salary affect the mean and median? How will increasing her salary affect the mean and median?

Mean increased

Median remains same

Step-by-step explanation:

Suzanne make $ 100 k per year

5 other employee  $ 40 k  to $ 50 K per year per employee

data in ascending order

$40000  , $40000+a  , $40000+b  , $40000+c   , $50000  , $ 100000

where 10000 ≥c ≥ b ≥ a ≥ 0

Mean = ($40000 + $40000+a + $40000+b  + $40000+c  + $50000 + $ 100000) /6

Mean = $(310000 + a + b + c)/ 6

Median = ($40000+b  + $40000+c )/2 =  $40000 + (b+c)/2

Suzanne make now $ 100000 + $  30000 = $ 130000 per year

$40000  , $40000+a  , $40000+b  , $40000+c   , $50000 , $ 130000

Mean = ($40000 + $40000+a + $40000+b  + $40000+c  + $50000 + $ 130000) /6

Mean = $(340000 + a + b + c)/ 6

Median = ($40+b k + $40+c k)/2 =  $40 + (b+c)/2 k

Mean increased by  $(340000 + a + b + c)/ 6 - $(310000 + a + b + c)/ 6

= $ 30000/6  = $ 5000

Median Remains the same

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".