I =
-2
g(x) = {(x - 1)(x + 2), r=-1
| 23 – 22 +1
, * # -2, -1
Mathematics, 06.05.2020 20:19 thickness7699
-343.
I =
-2
g(x) = {(x - 1)(x + 2), r=-1
| 23 – 22 +1
, * # -2, -1
g(1) =
Answers: 3
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You know the right answer?
-343.
I =
-2
g(x) = {(x - 1)(x + 2), r=-1
| 23 – 22 +1
, * # -2, -1
I =
-2
g(x) = {(x - 1)(x + 2), r=-1
| 23 – 22 +1
, * # -2, -1
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